Cyient Aptitude Questions and Answers For Freshers PDF Download

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Cyient Aptitude Questions and Answers with Explanation PDF Download: Are you preparing for the Cyient Placement Test? If yes, then go through our page. We have clearly provided the Cyient Aptitude Questions and Answers for Freshers with a clear explanation. So, those who want to prepare for the Cyient Placement Test can now check this article. We have even provided the direct link for the Cyient Aptitude Questions and Answers for Freshers PDF Download at the end of our page. More and more practice gives you to improve your time management skills.

Cyient Aptitude Questions and Answers For Freshers

Number of Questions: 15 Questions
Time Duration: 15 Mins 

Cyient Aptitude Questions and Answers in PDF Format

1. The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:

A. 15
B. 16
C. 18
D. 25

Answer – B. 16

Explanation:
Let the Cost Price of each article be Rs 1
Given, C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 – x).
((20 – x)/x) * 100 = 25
2000 – 100x = 25x
125x = 2000
Therefore, x = 16.

2. An article is sold at 25% profit. If the CP and the SP of the article are increased by Rs 60 and Rs 30, respectively, the profit percentage decreases by 15%. Find the cost price of the article.

A. Rs 190
B. Rs 240
C. Rs 285
D. Rs 305

Answer – B. Rs 240

Explanation:
CP = x
Then, SP = (125/100)*x = 5x/4
New CP = (x+60)
New SP = (5x/4 + 30)
New profit% = 25-15 = 10
So (5x/4 + 30) = (110/100) * (x+60)
Hence, x = 240

3. 5 kg of an article is bought at Rs 480, and 1/3rd of it is sold at a profit of 20%. At what loss% should the remaining article be sold so that there is an overall profit of 3 1/3%?

A. 5%
B. 6.5%
C. 7%
D. 8.5%

Answer – A. 5%

Explanation:
Let the remaining 2/3rd be sold at x% loss
1/3(20) + 2/3(-x) = 3 1/3 [x% loss, so used – sign] 1/3(20) + 2/3(-x) = 10/3
Solve, x = 5%

4. In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?

A. 30%
B. 70%
C. 100%
D. 250%

Answer – B. 70%

Explanation:
Let Cost Price= Rs. 100. Then, Profit = Rs. 320
Selling Price = Rs. 420.
C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs. 420.
Profit = Rs. (420 – 125) = Rs. 295.
Therefore, Required percentage = 295/420 * 100% = 1475/21% = 70% (Approximate Percentage)

5. A and B invested rupees 4000 and 5000, respectively, in a business. Being an active partner will get you rupee 50 extra every month for running the business. In a year, if A receives a total of 800 rupees, then what will B get from the business?

A. 200
B. 250
C. 300
D. 400

Answer – B. 250

Explanation:
The ratio in which the profit will be divided – 4:5.
A will get 50*12 = 600 rupees extra
So, business A got 200 rupees.
Then, (4/9)*P = 200, P = 450. So B will get 450 – 200 = 250 rupees

6. In a famous hotel, the rooms were numbered from 201 to 230. Each room gives an earning of Rs. 5000 for the first fifteen days of a month and for the latter half, Rs. 3000 per room. Find the average income per room per day over the month?

A. 2000
B. 3000
C. 4000
D. 5000

Answer – C. 4000

Explanation:
Total number of rooms = 29
Average = [(5000 * 30 * 15) + (3000 * 30 * 15)]/(30*30)
Average earning per room = 4000

7. A and B undertake to do a piece of work for Rs. 450. A can do it in 20 days, and B can do it in 40 days. With the help of C, they finished it in 8 days. How much should C be paid for his contribution?

A. Rs.50
B. Rs.60
C. Rs.90
D. Rs.180

Answer – D. Rs 180

Explanation:
A & B would have done 8/20 & 8/40 of the work, respectively, in 8 days.
Together they have done 3/5th of the work.
This implies that C has done 2/5th of the work.
Thus, C should be paid 2/5th of the amount, that is, 450 × 2/5 = Rs. 180.

8. P and Q can do a piece of work in 40 days, and Q and R can do it in 120 days. If Q alone can do it in 180 days, in how many days will P and R do it together?

A. 20 days
B. 25 days
C. 30 days
D. 45 days

Answer – D. 45 days

Explanation:
P + Q takes 40 days.
Q alone takes 180 days.
P will take 1/40 – 1/180 = 7/360 ⇒ 360/7 days.
Q + R takes 120 days.
Hence, R alone will take 1/120 – 1/180 = 1/360
It seems for 360 days.
Therefore, P & R together will take 7/360 + 1/360= 8/360 ⇒ 360/8 = 45
Therefore, it takes 45 days to complete the work.

9. 2 men and 3 women can together complete a piece of work in 4 days, and 3 men and 2 women together can complete the work in 3 days. In how many days will 10 women complete this work?

A. 6 days
B. 7 days
C. 9 days
D. 12 days

Answer – A. 6 days

Explanation:
Given that
2m + 3w = 4
3m + 2w = 3
So 4(2m + 3w) = 3(3m + 2w)
8m + 12w = 9m + 6w
6w = 1m
Given 2m + 3w = 4, so 2*(6w) + 3w = 4
Therefore, 15 women in 4 days
Hence, 10 women in (15*4)/10 = 6 days

10. 20 men can complete a piece of work in 14 days. 7 men started the work, and after 20 days, 7 more men joined the work. In how many days will the remaining work be completed?

A. 5 days
B. 10 days
C. 15 days
D. 20 days

Answer – B. 10 days

Explanation:
Let (7+7) complete the remaining work in x days. So
20*14 = 7*20 + 14*x
x = 10 days

11. A truck driving on a highway passed a man walking at the rate of 15km/hr in the same direction. He could see the truck for 2 minutes and up to 500 meters. Find the speed of the truck?

A. 27 km/hr
B. 30 km/hr
C. 32 km/hr
D. 42 km/hr

Answer – B. 30 km/hr

Explanation:
x-15=(500/120) *18/5
x=30

12. Varun traveled a distance of 50 km in 7 hrs. He traveled the distance partly on foot at 5 kmph and partly on a bicycle at 8 kmph. What is the distance that he traveled on foot?

A. 2 km
B. 5 km
C. 10 km
D. 18 km

Answer – C.10 km

Explanation:
x/5 + 50-x/8 =7
8x+250-5x = 7*40
3x+250 = 280
3x = 30
X = 30/3 = 10 km

13. The side of a square-shaped garden is 8√2. Find the maximum possible distance between any two corners

A. 15 meters
B. 16 meters
C. 17 meters
D. 18 meters

Answer – B. 16 meters

Explanation:
According to the given data
d = a√2
a = 8√2
d = 16 m

14. If the side of the square is increased by 30%, then how much % does its area increase?

A. 49%
B. 59%
C. 69%
D. 79%

Answer – C. 69%

Explanation:
Area of the plot = 1.3 * 1.3 = 1.69 = 69%

15. The length of a rectangle is reduced by 30%. By what percent would the width have to be increased to maintain the original area?

A. 25%
B. 32.76%
C. 35.50%
D. 42.86%

Answer – D. 42.86%

Explanation:
Width = 30*100/100-30
= 3000/70 = 42.86%

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